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If one root of the equation `x^(2)-lamdax+12=0` is even prime while `x^(2)+lamdax+mu=0` has equal roots, then `mu` isA. 8B. `16`C. `24`D. 32 |
Answer» Correct Answer - B Since 2 is only even prime. Therefore we have `2^(2)+lamda.2+12=0` `implieslamda=8` `:.x^(2)+lamdax+mu=0` `impliesx^(2)+8x+mu=0`….i But Eq. (i) has equal roots. `:.D=0` `implies 8^(2)-4.1=mu=0` `impliesmu=16` |
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