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If P and Q are two sets such that P has 40 elements, P ∪ Q has 60 elements and P ∩ Q has 10 elements, how many elements does Q have? |
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Answer» Given: n(P) = 40 n (P ∪ Q) = 60 n (P ∩ Q) =10 n(Q) = ? We know, n (P ∪ Q) = n(P) + n(Q) – n (P ∩ Q) Substituting the values we get 60 = 40+n(Q)–10 60 = 30+ n(Q) n(Q) =30 ∴ Q = has 30 elements. |
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