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    				| 1. | If P(n): 2 × 42n + 1 + 33n + 1 is divisible by λ for all n ∈ N is true, then find the value of λ. | 
| Answer» for n=1, 2×42×1+1 + 33×1+1=2×43+34 = 2×64+81 = 128+81 = 209 For n=2, 2×42×2+1 + 33×2+1 = 2×45+37 = 2×1024+2187 = 2048+2187 = 4235 Now, the H.C.F of 209 and 4235 is 11. Hence, λ=11. | |