1.

If P(n): 2 × 42n + 1 + 33n + 1 is divisible by λ for all n ∈ N is true, then find the value of λ.

Answer»

for n=1, 

2×42×1+1 + 33×1+1=2×43+34 

= 2×64+81 

= 128+81 

= 209 

For n=2, 

2×42×2+1 + 33×2+1 = 2×45+3

= 2×1024+2187 

= 2048+2187 

= 4235 

Now, the H.C.F of 209 and 4235 is 11. 

Hence, λ=11.



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