1.

If P(n) is the statement “n2 + n” is even”, and if P(r) is true, then P(r + 1) is true Given. P(n) = n2 + n is even and P(r) is true. Prove. P(r + 1) is true

Answer»

Given 

P(r) is true that means, 

= r2 + r is even 

Let Assume r2 + r = 2k - - - - - - (i) 

Now, (r + 1)2 + (r + 1) 

r2 + 1 + 2r + r + 1 

= (r2 + r) + 2r + 2 

= 2k + 2r + 2 

= 2(k + r + 1) 

= 2μ 

Therefore, (r + 1)2 + (r + 1) is Even. 

Hence, P(r + 1) is true



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