InterviewSolution
Saved Bookmarks
| 1. |
If P(n) is the statement “n2 + n” is even”, and if P(r) is true, then P(r + 1) is true Given. P(n) = n2 + n is even and P(r) is true. Prove. P(r + 1) is true |
|
Answer» Given P(r) is true that means, = r2 + r is even Let Assume r2 + r = 2k - - - - - - (i) Now, (r + 1)2 + (r + 1) r2 + 1 + 2r + r + 1 = (r2 + r) + 2r + 2 = 2k + 2r + 2 = 2(k + r + 1) = 2μ Therefore, (r + 1)2 + (r + 1) is Even. Hence, P(r + 1) is true |
|