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If p sec 50° = tan 50° then p is: (a) cos 50° (b) sin 50° (c) tan 50° (d) sec 50° |
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Answer» (b) sin 50° p sec 50° = tan 50° p(\(\frac{1}{cos50°}\)) = \(\frac{sin50°}{cos50°}\) ∴ p = sin 50° |
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