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If P(x,y) is equidistant from the points A(7,1) and B(3,5), find the relation between x and y. |
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Answer» Let the point P(x,y) be equidistant from the points A(7,1) and B(3,5) Then, PA = PB \(\Rightarrow\) PA2 = PB2 \(\Rightarrow\) (x - 7)2 + (y - 1)2 = (x - 3)2 + (y - 5)2 \(\Rightarrow\) x2 + y2 - 14x - 2y + 50 = x2 + y2 - 6x - 10y + 34 \(\Rightarrow\) 8x - 8y = 16 \(\Rightarrow\) x - y = 2 |
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