1.

If point P(2, 4) is equidistant from the points A(5, K) and B(K, 7), then find the value of K. 

Answer»

Point P(2, 4) is equidistant from the points A(5, K) and B(K, 7). 

So PA = PB

⇒ PA2 = PB2

⇒ (5 – 2)2 + (k – 4)2 = (k – 2)2 + (7 – 4)2

⇒ 9 + K2 + 16 – 8K = K2 + 4 – 4K + 9

⇒ K2 – 8K + 16 – K2 – 4 + 4K = 0

⇒ -4K + 12 = 0

⇒ -4K = -12

⇒ K = -12/-4 = 3

Hence, K = 3



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