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If points `hati+hatj, hati -hatj and p hati +qhatj+rhatk` are collinear, thenA. p=1B. r=0C. `q in R`D. `q ne 1` |
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Answer» Correct Answer - A::B::D Points `A(hati+hatj),B(hati-hatj) and C(phati+qhatj+rhatk)` are collinear Now, `AB=-2hatj` and `BC=(p-1)hati+(q+1)hatj+rhatk` Vectors AB and BC must be collinear `implies p=1,r=0 and q ne -1` |
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