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If position vector is given by R = (-6,-4,-)then the unit vector parallel to R is2.(2) 6i+4j+ 12k]14[6i+4j+12k) |
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Answer» Given the position is (-6,-4,-12) so, the vector R = -6i-4j-12kalso |R| = √(-6)²+(-4)²+(-12)² = √36+16+144 = √196 = 14 so, unit vector is given by = R/|R| = -6/14i -4/14j -12/14k= ±1/7(3i+2j+6k) option C |
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