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If radius of the `_(13)^(27) Al` necleus is estimated to be `3.6` fermithen the radius of `_(52)^(125)Te` nucleus be nearlyA. `8 fermi`B. `6 fermi`C. `5 fermi`D. `6 fermi` |
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Answer» Correct Answer - B KEY CONCEPT : `R = R_(0)(A)^(1//3)` `:. (R_(1))/(R_(2)) = (A_(1))/(A_(2))^(1//3) = ((27)/(125))^(1//3) = (3)/(5)` `R_(2) = (5)/(3) xx 3.6 = 6 fermi` |
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