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If S and T are two sets such that S has 21 elements, T has 32 elements and S∩T has 11 elements, how many elements does S∪T have? |
Answer» Given n(5) = 21; n(T) = 32; n(S∩T) = 11 n(S∪T) = n(S) + n(T) – n(S∩T) = 21 + 32-11 =42. |
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