If `S +O_(2) rarr SO_(2), DeltaH =- 298.2 kJ` `SO_(2)+1//2O_(2) rarr SO_(3), DeltaH =- 98.7 kJ` `SO_(3)+H_(2)O rarr H_(2)SO_(4), DeltaH =- 130.2 kJ` `H_(2) +1//2O_(2) rarr H_(2)O, DeltaH =- 287.3 kJ` Then the enthalpy of formation of `H_(2)SO_(4)` at `298K` isA. `-814.4` KJB. `-650.3` KJC. `-320.5` KJD. `-433.5` KJ

If `S +O_(2) rarr SO_(2), DeltaH =- 298.2 kJ` `SO_(2)+1//2O_(2) rarr S

1.	If `S +O_(2) rarr SO_(2), DeltaH =- 298.2 kJ` `SO_(2)+1//2O_(2) rarr SO_(3), DeltaH =- 98.7 kJ` `SO_(3)+H_(2)O rarr H_(2)SO_(4), DeltaH =- 130.2 kJ` `H_(2) +1//2O_(2) rarr H_(2)O, DeltaH =- 287.3 kJ` Then the enthalpy of formation of `H_(2)SO_(4)` at `298K` isA. `-814.4` KJB. `-650.3` KJC. `-320.5` KJD. `-433.5` KJ
Answer» Correct Answer - A `H_(2(g))+S_((s))+2O_(2(g))rarr H_(2)SO_(4) , Delta H_(f) = ?` Desired equation = eq(i) + eq(iii) + eq(iv) + eq(ii) `Delta H_(f)=(-298.2)+(-130.2)+(-287.3)+(-98.7)` `Delta H_(f)=-814.4 KJ`

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