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If `S={x:x^2+1=0,x` is real}, then S isA. `{-1}`B. {0}C. {1}D. an empty set |
Answer» Correct Answer - D `S={x : x^(2)+1=0, x: 5" real"}` `x^(2)+1=0impliesx^(2)=-1impliesx=sqrt(-1)rarr` complex number No real numbers. So, S is empty set |
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