1.

If sec (3x – 20)° = cosec (3y + 20)°, what is the value of tan (x + y)?1). 12). √33). 1/√34). 2√3

Answer»

Since we know that SEC(x) = cosec (90 - x), From the given equation

⇒ sec (3x – 20) = sec{90 – (3y + 20)} comparing the terms in BRACKETS on LHS and RHS

⇒ 3x - 20 = 90 – (3y + 20)

⇒ x + y = 30

TAN(x + y) = tan(30) = 1/√3


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