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If sec θ + tan θ = 2, then sec θ is equal to1). \(\frac{7}{4}\)2). \(\frac{7}{2}\)3). \(\frac{5}{2}\)4). \(\frac{5}{4}\) |
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Answer» We KNOW that, Sec2 θ – tan2 θ = 1 Using (a2 – B2) = (a – b)(a +b), we GET (Sec θ + tan θ)(Sec θ - tan θ) = 1 Given, sec θ + tan θ = 2 . . . . . . . eq (i) ⇒ (Sec θ – tan θ) = 1/2 ....... eq (ii) Now, adding eq (i) and (ii), we get ⇒ 2 Sec θ = 2 + ½ ⇒ 2Sec θ = 5/2 ⇒ secθ = 5/4 |
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