1.

If sec θ + tan θ = 2, then sec θ is equal to1). \(\frac{7}{4}\)2). \(\frac{7}{2}\)3). \(\frac{5}{2}\)4). \(\frac{5}{4}\)

Answer»

We KNOW that,

Sec2 θ – tan2 θ = 1

Using (a2 B2) = (a – b)(a +b), we GET

(Sec θ + tan θ)(Sec θ - tan θ) = 1

Given, sec θ + tan θ = 2 . . . . . . . eq (i)

⇒ (Sec θ – tan θ) = 1/2 ....... eq (ii)

Now, adding eq (i) and (ii), we get

⇒ 2 Sec θ = 2 + ½

⇒ 2Sec θ = 5/2

⇒ secθ = 5/4


Discussion

No Comment Found