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If `sin^(- 1)(3/x)+sin^(- 1)(4/x)=pi/2` then `x=`A. 3B. 5C. 7D. 11 |
Answer» We have `sin^(-1)(3)/(x)+sin^(-1)(4)/(x)=(pi)/(2)` `rarr sin^(-1)(3)/(x)=(pi)/(2)-sin^(-1)(4)/(x)` `rarr sin^(-1)(3)/(x)=cos^(-1)(4)/(x)` `rarr sin^(-1) (3)/(x)=sin^(-1)(sqrt(x^(2)-16)/(x))` `rarr(3)/(x)=sqrt(x^(2))=-16)/(x)rarrx=5` |
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