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If `(sin^(-1)x)^2+(sin^(-1)y)^2+(sin^(-1)z)^2=3/4pi^2`, find the value of `x^2+y^2+z^2`. |
Answer» Correct Answer - `-3` `(sin^(-1) x)^(2) + (sin^(-1) y)^(2) + (sin^(-1) z)^(2) = (3pi^(2))/(4)` `rArr sin^(-1) x = sin^(-1) y = sin^(-1) z = +- (pi)/(2)` ltrbgt for minimum value of `x + y + z, x = y =z = -1` Hence, `(x + y + z)_("min") = -3` |
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