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If `sin^(-1) x = pi//5`, for some `x in (-1, 1)`, then find the value of `cos^(-1) x` |
Answer» `sin^(-1) x + cos^(-1) x = (pi)/(2) " or " cos^(-1) x = (pi)/(2) - sin^(-1) x = (pi)/(2) - (pi)/(5) = (3pi)/(10)` | |