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If `sin^-1 x+sin^-1=(2pi)/3,` then `cos^-1 x cos^-1 y` is equal to |
Answer» Correct Answer - `(pi)/(3)` `sin^(-1) x + sin^(-1) y = (2pi)/(3)` `rArr (pi)/(2) - cos^(-1) x + (pi)/(2) - cos^(-1) y = (2pi)/(3)` `rArr cos^(-1) x + cos^(-1) y = pi - (2pi)/(3) = (pi)/(3)` |
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