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If `sin^-1 x+sin^-1y=(2pi)/3,` then `cos^-1 x +cos^-1 y` is equal toA. `(2pi)/(3)`B. `(pi)/(3)`C. `(pi)/(6)`D. `pi` |
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Answer» We have `sin^(-1)x+sin^(-1)y=(2pi)/(3)` `rarr (pi)/(2) cos^(-1)x+(pi)/(2)-cos^(-1)y=(2pi)/(3)` `rarr cos^(-1)x+cos^(-1)y=pi-(2pi)/(3)=(pi)/(3)` |
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