1.

If `(sin^(2)theta-5sintheta+3)/(cos^(2)theta)`=1, then `theta` can be _______.A. `30^(@)`B. `45^(@)`C. `60^(@)`D. `0^(@)`

Answer» Correct Answer - A
`sin^(2)theta-5sintheta+3=cos^(2)theta`
`rArrsin^(2)theta-5sintheta+3=1-sin^(2)theta`
`rArr2sin^(2)theta-5sintheta+2=0`
`rArr(2sintheta-1)(sintheta-2)=0`
`But sintheta=2` is not possible
`thereforesintheta=(1)/(2)rArrtheta=30^(@)`


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