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If `(sin^(2)theta-5sintheta+3)/(cos^(2)theta)`=1, then `theta` can be _______.A. `30^(@)`B. `45^(@)`C. `60^(@)`D. `0^(@)` |
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Answer» Correct Answer - A `sin^(2)theta-5sintheta+3=cos^(2)theta` `rArrsin^(2)theta-5sintheta+3=1-sin^(2)theta` `rArr2sin^(2)theta-5sintheta+2=0` `rArr(2sintheta-1)(sintheta-2)=0` `But sintheta=2` is not possible `thereforesintheta=(1)/(2)rArrtheta=30^(@)` |
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