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If sin(3θ)sec(2θ) = 1, then what is the value of [3tan2(5θ/2) – 1]?1). 02). 13). 24). 3 |
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Answer» ⇒ sin3θ = 1/sec2θ ⇒ cos(π/2 – 3θ) = cos2θ ⇒ π/2 – 3θ = 2θ ⇒ π/2 = 5θ ⇒ θ = π/10 To FIND: [3tan2(5θ/2) – 1] ⇒ 3tan2(π/4) – 1 ⇒ 3 × 1 – 1 = 2 ∴ the CORRECT option is 3) |
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