1.

If sin(3θ)sec(2θ) = 1, then what is the value of [3tan2(5θ/2) – 1]?1). 02). 13). 24). 3

Answer»

⇒ sin3θ = 1/sec2θ

⇒ cos(π/2 – 3θ) = cos2θ

⇒ π/2 – 3θ = 2θ

⇒ π/2 = 5θ

⇒ θ = π/10

To FIND: [3tan2(5θ/2) – 1]

⇒ 3tan2(π/4) – 1

3 × 1 – 1 = 2

∴ the CORRECT option is 3)


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