If `sin alpha+ cos alpha=n`, then ` sin^(6)alpha+ cos^(6)alpha` in terms of n is ________A. `4+3(n-1)^(2)`B. `(4+3(n^(2)-1))/(4)`C. `4-3(n^(2)-1)^(2))/(4)`D. None of these

If `sin alpha+ cos alpha=n`, then ` sin^(6)alpha+ cos^(6)alpha` in ter

1.	If `sin alpha+ cos alpha=n`, then ` sin^(6)alpha+ cos^(6)alpha` in terms of n is ________A. `4+3(n-1)^(2)`B. `(4+3(n^(2)-1))/(4)`C. `4-3(n^(2)-1)^(2))/(4)`D. None of these
Answer» Correct Answer - C (i) `sin^(6)alpha+cos^(6)alpha=(sin^(2)alpha)^(3)+(cos^(2)alpha)^(3)`. Use the formula ` a^(3)+b^(3)=(a+b)^(3)=3ab(a+b)`. (ii) Find `sin alpha* cos alpha ` by substituting ` sin alpha+ cos alpha=n` in the above equations.