1.

If Sin θ = 1/3 ,then Cos θ will be-​

Answer»

EXPLANATION:

SIN A =p/h

p/h=1/3

p=1,h=3,B=?

by PYTHAGORAS THEOREM

h^2=p^2+b^2

3^2=1^2+b^2

9-1=b^2

b^2=8

b=2√2

cos A=b/h

=2√2/3



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