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If Sin θ = 1/3 ,then Cos θ will be- |
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Answer» SIN A =p/h p/h=1/3 p=1,h=3,B=? h^2=p^2+b^2 3^2=1^2+b^2 9-1=b^2 b^2=8 b=2√2 cos A=b/h =2√2/3 |
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