InterviewSolution
Saved Bookmarks
| 1. |
If `sum_(k=1)^(n)k=45,` find the value of `sum_(k=1)^(n)k^(3).` |
|
Answer» Correct Answer - 2025 Given `(1+2+3+...+n)=45 rArr (1)/(2)n(n+1)=45.` `therefore (sum_(k=1)^(n)k^(3))={(1)/(2)n(n+1)}^(2)=(45)^(2)=2025.` |
|