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If sum of the 3rd and the 8th terms of an AP is 7 and the sum of the 7th and 14th terms is - 3, then find the 10th term. |
Answer» Let the first term and common difference of an AP are a and d, respectively. Given a3 + a8 = 7 As we know, nth term of an AP is an = a + (n - 1)d where a = first term an is nth term d is the common difference a + 2d + a + 7d = 7 2a + 9d = 7 2a = 7 - 9d [ Eqn 1] a7 + a14 = - 3 a + 6d + a + 13d = - 3 2a + 19d = - 3 7 - 9d + 19d = - 3 [ using eqn i] 7 + 10d = - 3 10d = - 10 d = - 1 using this value in eqn i 2a = 7 - 9 (- 1) 2a = 16 a = 8 Now, a10 = a + 9d = 8 + 9 (- 1) = 8 - 9 = - 1 |
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