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If `tan^-1(1/y)=-pi+cot^-1 y,` where `y=x^2-3x+2,` then find the value of `x` |
Answer» Correct Answer - `x in (1, 2)` `tan^(-1) ((1)/(y)) = -pi + cot^(-1) y` `rArr y lt 0` `rArr x^(2) - 3x + 2 lt 0` `rArr (x - 1) (x -2) lt 0` `rArr x in (1, 2)` |
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