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If `tan^(-1)x+2cot^(-1)x=(2pi)/(3)` then x =A. 3B. `sqrt(3)`C. `sqrt(2)`D. `(sqrt(3)-1)/(sqrt(3)+1)` |
Answer» We have `tan^(-1)x+2cot(-1)x=(2pi)/(3)` `rarr tant^(-1)x+2(pi)/(2)-tan^(-1)x=(2pi)/(3)rarr tan^(-1)x=(n)/(3)rarrx=sqrt(3)` |
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