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If tan 2A = cot (A – 18°), where 2A is an acute angle. Find the value of A. |
Answer» Given that tan 2A = cot (A – 18°) ⇒ cot (90° – 2A) = cot (A – 18°) [∵ tan θ = cot (90 – θ)] ⇒ 90° – 2A = A – 18° ⇒ 108° = 3A ⇒ A = 108° / 3 = 36° Hence the value of A is 36°. |
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