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If tan2 y cosec2 x – 1 = tan2 y, then which one of the following is correct?(a) x – y = 0 (b) x = 2y (c) y = 2x (d) x – y = 1° |
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Answer» (a) x – y = 0 tan2 y cosec2 x – 1 = tan2 y ⇒ tan2 y cosec2 x – tan2 y = 1 ⇒ tan2 y (cosec2 x – 1) = 1 ⇒ tan2 y . cot2 x = 1 ⇒ cot2 x = cot2 y ⇒ x = y ⇒ x – y = 0. |
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