If `tanx=b/a` then `sqrt((a+b)/(a-b))+sqrt((a-b)/(a+b))=` – InterviewSolution

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1.	If `tanx=b/a` then `sqrt((a+b)/(a-b))+sqrt((a-b)/(a+b))=`
Answer» `tanx=b/a` `b=atanx` `sqrt((a+b)/(a-b))+sqrt((a-b)/(a+b))` `(a+b+a-b)/(sqrt(a-b)sqrt(a+b))=2/sqrt(a^2-b^2` `(2a)/sqrt(a-(atanx)^2` `(2a)/sqrt(a^2(1-tan^2x)` `2/sqrt(1-tan^2x` `(2cosx)/sqrt(cos^2x-sin^2x` `(2cosx)/sqrt(cos2x)`

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