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If the 4th, 10th and 16th terms of a G.P. are x, y and z respectively. Prove that x, y, z are in G.P. |
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Answer» Let first term of GP be a and common ratio be r As nth term of GP is given as – Tn = arn – 1 ∴ T4 = ar4 – 1 = ar3 Similarly T10 = ar9 And T16 = ar15 ∴ x = ar3, y = ar9 & z = ar15 Clearly we observed that x, y, z have a common ratio. ∴ x,y,z are in GP with common ratio r6. Hence proved. |
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