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If the 5th term of a GP is 2, find the product of its first nine terms. |
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Answer» Given: 5th term of a GP is 2. To find: the product of its first nine terms. First term is denoted by a, the common ratio is denote by r. ∴ ar4 = 2 We have to find the value of: a × ar1 × ar2 × ar3 × … × ar8 = a9r1 + 2 + 3 + 4 + … + 8 = a9r36 = (ar4)9 = (2)9 = 512 . |
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