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If the atomic number of some element in the modern periodioc table are8,7,11,12,13 and 9 what type of ions do they form ? Arrange the ions in the increasing order of their size and justify |
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Answer» Solution :The elements with atomic number 8,7,11,12,13 and 9 are OXYGEN nitrogen sodium magnesium aluminumum and fluoringe respectively .These elements belons to VIA (16),VA(15),IA(1),IIA(2),IIIA(13)and VIIA(17)groups .generally these elements form `O^(-2),N^(-3),Na^(+),Mg^(+2),AI^(3+)` and `F^(-)` ions The order of ionic size is `Z^(-3)GTO^(-2)gtF^(-)gtNa^(+)gtMg^(+2)gtAI^(3+)` |
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