InterviewSolution
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InterviewSolution
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If the average of m numbers is n2 and that of n numbers is m2 , then the average of (m + n) numbers is (a) m – n (b) mn (c) (m + n) (d) m/n |
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Answer» Answer is: (d) mn Average of m numbers = n2 ∴ Sum of m numbers = m × n2 = mn2 Average of n numbers = m2 ∴ Sum of n numbers = n × m2 = m2n ∴ Required average = \(\frac{mn^2+nm^2}{m+n}=\frac{mn(n+m)}{m+n}=mn\) |
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