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The average of the squares of the first ten natural numbers is(a) 40 (b) 50 (c) 47.5 (d) 38.5 |
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Answer» Answer is: (d) 38.5 Average = \(\frac{1^2+2^2+3^2+4^2+5^2+6^2+7^2+8^2+9^2+10^2}{10}=\) \(\frac{1+4+9+16+25+36+79+64+81+100}{10}\) \(=\frac{385}{10}=38.5\) |
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