1.

The average of the squares of the first ten natural numbers is(a) 40 (b) 50 (c) 47.5 (d) 38.5

Answer»

Answer is: (d) 38.5

Average = \(\frac{1^2+2^2+3^2+4^2+5^2+6^2+7^2+8^2+9^2+10^2}{10}=\) \(\frac{1+4+9+16+25+36+79+64+81+100}{10}\)

\(=\frac{385}{10}=38.5\)



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