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The average price of 10 books is Rs 12, while the average price of 8 of these books is Rs 11.75. Of the remaining two books, if the price of one is 60% more than the price of the other, what is the price of each of these two books ? (a) Rs 8; Rs 12 (b) Rs 10; Rs 16 (c) Rs 5; Rs 7.50 (d) Rs 12; Rs 14 |
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Answer» Answer is: (b) Rs 16. Total price of the remaining two books = 10 × 12 – 8 × 11.75 = 120 – 94 = Rs 26 Suppose the price of one book = Rs x Then, price of the other book = x + 60% of x = \(\frac{160}{100}\) x = \(\frac{8x}{5}\) Given, x + \(\frac{8x}{5}\) = 26 ⇒ \(\frac{13x}{5}\) = 26 ⇒ x = \(\frac{26\times5}{13}\) = Rs 10 ∴ Price of the other book = Rs \(\frac{8\times10}{5}\) = Rs 16. |
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