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If the binding energy per nucleon in `_(3)^(7) Li and _(2)^(4)He nuclei are 5.60 MeV and 7.06MeV` respectively then in the reaction `P +_(3)^(7) Li rarr 2 _(2)^(4) He` energy of proton mnust beA. `28.24 MeV`B. `17.28 MeV`C. `1.46 MeV`D. `39.2 MeV` |
Answer» Correct Answer - B Let `E` be the energy of proton , than `E + 7 xx 5.6 = 2 xx [4 xx 7.06]` `rArr E = 56.48 - 39.2 = 17.28MeV` |
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