If the boundary of system moves by an infinitesimal amount, the work involved is given by `dw=-P_("ext")dV` for irreversible process `w=-P_("ext")DeltaV " "( "where "DeltaV=V_(f)-V_(i))` for reversible process `P_("ext")=P_("int")pmdP~=P_("int")` so for reversible isothermal process `w = -nRTln.(V_(f))/(V_(i))` 2mole of an ideal gas undergoes isothermal compression along three different plaths : (i) reversible compression from `P_(i)=2` bar and `V_(i) = 8L` to `P_(f) = 20` bar (ii) a single stage compression against a constant external pressure of 20 bar, and (iii) a two stage compression consisting initially of compression against a constant external pressure of 10 bar until `P_("gas")=P_("ext")`, followed by compression against a constant pressure of 20 bar until `P_("gas") = P_("ext")` Work done (in bar-L) on the gas in reversible isothermal compression is :A. 9.212B. 36.848C. 18.424D. None of these

If the boundary of system moves by an infinitesimal amount, the work i

1.	If the boundary of system moves by an infinitesimal amount, the work involved is given by `dw=-P_("ext")dV` for irreversible process `w=-P_("ext")DeltaV " "( "where "DeltaV=V_(f)-V_(i))` for reversible process `P_("ext")=P_("int")pmdP~=P_("int")` so for reversible isothermal process `w = -nRTln.(V_(f))/(V_(i))` 2mole of an ideal gas undergoes isothermal compression along three different plaths : (i) reversible compression from `P_(i)=2` bar and `V_(i) = 8L` to `P_(f) = 20` bar (ii) a single stage compression against a constant external pressure of 20 bar, and (iii) a two stage compression consisting initially of compression against a constant external pressure of 10 bar until `P_("gas")=P_("ext")`, followed by compression against a constant pressure of 20 bar until `P_("gas") = P_("ext")` Work done (in bar-L) on the gas in reversible isothermal compression is :A. 9.212B. 36.848C. 18.424D. None of these
Answer» Correct Answer - B `DeltaU=-300+(-50-150)=-500` `T= 100 K` `w_("rev")=-2.303xxnxxRxxTlog.(P_(1))/(P_(2))` `=-2.303xx2xx0.08xx100xxlog((1)/(10))` `=36.848 " bar-L"`

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