1.

If the coefficient of performance of a refrigerator is 5 and operates at the room temperature (`27^(@)` C), find the temperature inside the refrigerator.A. 240 KB. 250 KC. 230 KD. 260 K

Answer» Correct Answer - B
Here coefficient of performance `beta`=5
`t_(1)=27^(@)C=(27+273)K=300K`
As `beta =(T_(2))/(T_(1)-T_(2)), rArr 5 =(T_(2))/(300-T_(2))`
or `1500-5T_(2)=t_(2)or 6T_(2)=1500`
`therefore T_(2)=(1500)/(6)=250 K`


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