1.

if the distance between two equal point charges is doubled and their individual charges are also doubled,what would happen to the force between them​

Answer»

Explanation:

▪️Initial force ⇒F=Kr2qq

▪️Final force ⇒F=K(2r)2(2Q)(2q)=4r24Kqq=r2Kqq

▪️Thus, the force will REMAIN UNCHANGED.

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