If the electron of hydrogen atom takes 3.2*10^-17 sec to complete one

1.	If the electron of hydrogen atom takes 3.2*10^-17 sec to complete one revolution, then how much current is consituted
Answer» $\huge\underline{\underline{\bf \orange{Question-}}}$ If the ELECTRON of HYDROGEN atom takes ${\sf 3.2×10^{-17}\:sec}$ to complete ONE revolution, then how much CURRENT is consituted $\huge\underline{\underline{\bf \orange{Solution-}}}$ $\large{\rm We \: Know \: That - }$ $\large{\boxed{\bf \blue{I = \dfrac{Q}{t}}}}$ t = ${\sf 3.2×10^{-17}\:sec}$ And charge on one electron is ${\sf 1.6×10^{-19}C}$ . So , $\implies{\sf I = \dfrac{1.6×10^{-19}}{3.2×10^{-17}} }$ $\implies{\sf I = 0.5×10^{-19+17} }$ $\implies{\sf I = 0.5×10^{-2}}$ $\implies{\bf \red{Current\:(I )= 5×10^{-3}\:A}}$ $\huge\underline{\underline{\bf \orange{Answer-}}}$ Current is consituted ${\bf \red{Current\:(I )= 5×10^{-3}\:A}}$ .