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If the enthalpy of combustion of `C`(graphite) is `-393.3kJ mol^(-1)`, then for producing `39.3kJ` of heat the amount of carbon required isA. `1.5 mol`B. `0.5mol`C. `1.2 g`D. `12 mg` |
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Answer» `393.3 kJ` enegry produced by `12 gC` Therefore, `39.3 kJ` enegry produced by `(12 xx39.3)/(393.3) = 1.2 g of C` (graphite) |
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