InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
If the equation `sin^(-1)(x^2+x+1)+cos^(-1)(lambda+1)=pi/2`has exactly two solutions for `lambda in [a , b]`, then the value of `a+b`is |
|
Answer» Correct Answer - 1 `sin^(-1) (x^(2) + x -1) + cos^(-1) (lamda x + 1) = (pi)/(2)` `rArr x^(2) + x + 1 = lamda x + 1` `rArr x^(2) + (1- lamda) x = 0` `rArr x = 0 " or " x = lamda -1` Also, `sin^(-1) (x^(2) + x + 1)` will exist if `-1 le x^(2) + x + 1 le 1` `rArr x^(2) + x le 0 rArr -1 le x lt 0` For exactly two solution, we have `-1 le lamda -1 lt 0` `rArr 0 le lamda lt 1` `:. a = 0 and b =1` |
|