1.

If the excess pressure inside a spherical soap bubble of radius 1 cm is balanced by that due to column of oil of specific gravity 0.9, height 1.36 mm. Calculate the value of surface tension of soap solution.

Answer» Here, `r=1 cm`
density `rho = sp.gravity xx density` of water
`= 0.9 xx 1 = 0.9 g//c c`
`h=1.36 mm = 0.136 cm`
Given excess pressure in a soap bubble
= pressure due to column of oil of height h
So, `(4S)/(r ) = h rho g`
or `S= (h rho g r)/(4) = (0.136 xx 0. 9 xx 980 xx 1)/(4)`
`= 29.988 dyn e//cm`.


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