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If the excess pressure inside a spherical soap bubble of radius 1 cm is balanced by that due to column of oil of specific gravity 0.9, height 1.36 mm. Calculate the value of surface tension of soap solution. |
Answer» Here, `r=1 cm` density `rho = sp.gravity xx density` of water `= 0.9 xx 1 = 0.9 g//c c` `h=1.36 mm = 0.136 cm` Given excess pressure in a soap bubble = pressure due to column of oil of height h So, `(4S)/(r ) = h rho g` or `S= (h rho g r)/(4) = (0.136 xx 0. 9 xx 980 xx 1)/(4)` `= 29.988 dyn e//cm`. |
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