1.

If the fifth term of a G.P. is 2, then write the product of its 9 terms.

Answer»

Given : Fifth term of GP is 2

⇒ Let the first term be a and the common ratio be r.

∴ According to the question,

T5 = 2

We know,

an = arn-1

a5 = a.r5-1

2 = ar4

GP = a,ar,ar2,…,ar8

Product required = a×ar×ar2×…×ar8

= a9.r36

= (ar4)9

= (2)9

= 512



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