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If the fifth term of a G.P. is 2, then write the product of its 9 terms. |
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Answer» Given : Fifth term of GP is 2 ⇒ Let the first term be a and the common ratio be r. ∴ According to the question, T5 = 2 We know, an = arn-1 a5 = a.r5-1 2 = ar4 GP = a,ar,ar2,…,ar8 Product required = a×ar×ar2×…×ar8 = a9.r36 = (ar4)9 = (2)9 = 512 |
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