

InterviewSolution
Saved Bookmarks
1. |
If the half life period of a first order reaction is `2.31 xx 10^(3)` minutes, how long will it take for `1//5`th of the reactant to be left behind? |
Answer» `k=2.303/k log a/(a-x)` `t=(2.303)/(3.0 xx 10^(-4) mm^(-1)) log a/(a//5) = (2.303 xx 0.699)/(3.0 xx 10^(-4) min^(-1))` `=0.536 xx 10^(4) mm=5.36 xx 10^(3)` min |
|