1.

If the half life period of a first order reaction is `2.31 xx 10^(3)` minutes, how long will it take for `1//5`th of the reactant to be left behind?

Answer» `k=2.303/k log a/(a-x)`
`t=(2.303)/(3.0 xx 10^(-4) mm^(-1)) log a/(a//5) = (2.303 xx 0.699)/(3.0 xx 10^(-4) min^(-1))`
`=0.536 xx 10^(4) mm=5.36 xx 10^(3)` min


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