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If the half-life period of a first order reaction is 138.6 min, then the value of decay constant for the reaction will be `("in min"^(-1))`A. 5B. 0.5C. 0.05D. 0.005 |
Answer» Correct Answer - D `lambda=(0.693)/(t_(1//2)),Given, t_(1//2)=138.6min` `therefore" "lambda=(0.693)/(138.6)=0.005"min"^(-1)` |
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