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If the intensity increased by a factor of 20, byhow may decibels is the sound level increased? |
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Answer» Let the initial intensity be I and te sound level be `beta_1`. When the intensity is increased to 20 I, the level increases to `beta_2`. `Then beta_1=10log(I/I_0)` and `beta_2=10log(20I/I)` `Thus, beta_2-beta_1=10log(20I/I)` `=10log 20` `=13dB`. |
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