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If the line `a x+b y+c=0`is a normal to the curve `x y=1,`then`a >0,b >0``a >0,b |
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Answer» Correct Answer - B::C Given, `" " xy = 1 rArr y = (1)/(x)` `rArr " " (dy)/(dx) = - (1)/(x^(2))` Thus, slope of normal = `x^(2)` ( which is always positive) and it is given `ax + by + c =0` is normal, whose slope `= -(a)/(b)`. `rArr " " - (a)/(b) gt 0 or (a)/(b) lt 0` Hence, a and b are of opposite sign. |
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